Andrew Thangaraj
Aug-Nov 2020
\(T:V\to W\) is a linear map. The null space of \(T\), denoted null \(T\), is defined as \[\text{null } T=\{v\in V:Tv=0\}.\] null \(T\): subset of vectors that get mapped to 0 by \(T\)
Examples
\(T:V\to W\) is a linear map. null \(T\) is a subspace of \(V\).
Proof: If \(u,v\in\text{null }T\), \(au+bv\in\text{null }T\)
Corollary: A linear map \(T\) always maps \(0\) to \(0\).
A map \(T:V\to W\) is said to be injective if \(Tu=Tv\) implies \(u=v\).
Examples: identity, multiplication by \(x^2\) are injective; zero, differentiation are not injective
A linear map \(T:V\to W\) is injective iff null \(T=\{0\}\).
\(T:V\to W\) is a map. The range of \(T\), denoted range \(T\), is defined as \[\text{range } T=\{Tv:v\in V\}.\] range \(T\): set of outputs of \(T\)
Examples
\(T:V\to W\) is a linear map. range \(T\) is a subspace of \(W\).
Proof
If \(w_1,w_2\in\text{range }T\), we have \(Tv_1=w_1\) and \(Tv_2=w_2\)
\(aw_1+bw_2=T(av_1+bv_2)\in\text{range }T\)
A map \(T:V\to W\) is said to be surjective if range \(T=W\).
Examples
Suppose \(V\) is finite-dimensional and \(T:V\to W\) is a linear map. Then, range \(T\) is finite-dimensional and \[\text{dim } V = \text{dim null } T + \text{dim range } T\]
Proof sketch
\(\{u_1,\ldots,u_k\}\): basis for null \(T\)
\(\{u_1,\ldots,u_k,v_1,\ldots,v_l\}\): extension of above basis to basis of \(V\)
Show \(\{Tv_1,\ldots,Tv_l\}\) is a basis for range \(T\)
\(T:V\to W\) is a linear map, \(V\): finite-dimensional
null \(T\): mapped to \(0\)
\(\{u_1,\ldots,u_k\}\): basis for null \(T\)
\(\{u_1,\ldots,u_k,v_1,\ldots,v_l\}\): extension
Vectors of the form: \(av_1+\) vector from null \(T\)
Vectors of the form: \(bv_2+\) vector from null \(T\)
and so on…
Each mapping above is to linearly independent vectors